Challenges
Challenge 1 — Maximum torque with F = 10 N
Set the perpendicular distance to maximize the turning effect.
Current τ = 2.00 N·m — push d higher.
Challenge 2 — Spin the wheel with the smallest force
Reach ω = 4 rad/s in 2 s (I = 0.5 kg·m², arm = 0.5 m). Find the smallest F that works (≤ 12 N is excellent).
Need τ ≥ 1.00 N·m. You have τ = 10.00.
Challenge 3 — Open the door with minimum effort
Where should you push?
Try pushing further from the hinges. (Current: 40% along the door.)
Challenge 4 — Pick the best spanner
You need τ = 40 N·m. Choose a handle length that needs the smallest force.
Length = 15 cm → F = 267 N. Can you do better?